tentukan persamaan garis lurus jika diketaui A.melalui titik (1,6) dan (7,4) MOHON DIJAWAB !!!

[tex] \frac{y - y_1}{y_2 - y_1} = \frac{x- x_1}{x_2 - x_1} \\ \frac{y - 6}{4 - 6} = \frac{x - 1}{7 - 1} \\ 6(y - 6) = -2(x - 1) \\ 6y - 36 = - 2x + 2 \\ 2x + 6y - 38 = 0[/tex]

y-y1/y2-y1 = x-x1/x2-x1
y-6/4-6= x-1/7-1
y-6/-1=x-1/6
6(y-6)=-1(x-1)
6y-36=-x-1
6y=-x-1+36
6y=-x+35
y=(-x+35)/6