persamaan kuadrat 2-6x-x^2=0 memiliki akar-akar alpha dan beta , nilai (alpha^2).beta dan (alphabeta)^2 dengan akar-akar persamaan kuadrat tersebut adalah..

jawab

- x² -6x + 2= 0
a = - 1
b = -6
c = 2

α+β = -b/a = -6
α β =  c/a = - 2

α²β + αβ² = αβ(α+β) = (-2)(-6) = 12

alpa = x1
betha = x2

-x^2 -6x+2 = 0

x^2 + 6x - 2 = 0

a = 1 , b = 6 , c = -2

x1 + x2 = -b/a = -6

x1.x2 = c/a = -2

x1^2 . x2 + x1 . x2^2

= x1.x2 (x1 + x2)

= -2 (-6)

= 12