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Pertanyaan

hitunglah pH larutan 500 ml HNO³ 0,01 M

1 Jawaban

  • HNO3 -> H+ + NO3-

    [H+] = a. Ma
    [H+] = koefisien H+ / koefisien HNO3. Ma
    [H+] = 1/1. 0,01
    [H+] = 0,01 M = 10^-2 M

    pH = - log [H+]
    pH = - log 10^-2
    pH = - (-2)
    pH = 2

    Semoga bisa bantu

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