Matematika

Pertanyaan

jika sin A = 3/5 dan cot B = 24/7 maka sin (A-B) adalah...

1 Jawaban

  • sinA=3/5, cosA=4/5, cotB=24/7, cosB/sinB=24/7
    cosB=24/25, sinB=7/25

    sin(A-B)=sinAcosB-cosAsinB
    =(3/5)(24/25)-(4/5)(7/25)
    =72/125 - 28/125
    =44/125

Pertanyaan Lainnya