tolong bantu ya 6 1per4 di+4 1per2 dix 2per3 di: 3 1per4 samadengan 18 13per20+7 3per5:3 4per5x2 1per4 samadengan pake cara y
Matematika
bhenyajjah
Pertanyaan
tolong bantu ya
6 1per4 di+4 1per2 dix 2per3 di: 3 1per4 samadengan
18 13per20+7 3per5:3 4per5x2 1per4 samadengan
pake cara y
6 1per4 di+4 1per2 dix 2per3 di: 3 1per4 samadengan
18 13per20+7 3per5:3 4per5x2 1per4 samadengan
pake cara y
1 Jawaban
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1. Jawaban kautsarmus
6¼+4½×⅔:3¼
=6¼+ (9/2×2/3:13/4)
=6¼ + (9/3×4/13)
=6¼ + 36/39
=6¼ + 12/13
=6+(13/52+48/52)
=6+(61/52)
=6+1+9/52
=7 9/52
≈7,17
18 13/20 + 7 3/5 : 3 4/5 × 2 ¼
=18 13/20 + 38/5 :19/5 × 9/4
=18 13/20 + 38/5 × 5/19 × 9/4
=18 13/20 + 9/2
=18 13/20 + 4 ½
=18+4+(13/20+½)
=22+(13/20+10/20)
=22+1+3/20
=23 3/20
≈23,15