Matematika

Pertanyaan

tolong bantu ya
6 1per4 di+4 1per2 dix 2per3 di: 3 1per4 samadengan

18 13per20+7 3per5:3 4per5x2 1per4 samadengan

pake cara y

1 Jawaban

  • 6¼+4½×⅔:3¼
    =6¼+ (9/2×2/3:13/4)
    =6¼ + (9/3×4/13)
    =6¼ + 36/39
    =6¼ + 12/13
    =6+(13/52+48/52)
    =6+(61/52)
    =6+1+9/52
    =7 9/52
    ≈7,17

    18 13/20 + 7 3/5 : 3 4/5 × 2 ¼
    =18 13/20 + 38/5 :19/5 × 9/4
    =18 13/20 + 38/5 × 5/19 × 9/4
    =18 13/20 + 9/2
    =18 13/20 + 4 ½
    =18+4+(13/20+½)
    =22+(13/20+10/20)
    =22+1+3/20
    =23 3/20
    ≈23,15

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