Matematika

Pertanyaan

2log 16 - 3log 27 + 5log 1

2 Jawaban

  • =2'log 16 - 3'log 27 + 5'log 1
    =2'log 2^4 - 3'log 3^3 + 5'log 5^0
    =4 - 3 + 0
    =1

    semoga membantu

    a'log a^b = b (sifat logaritma)
  • [tex] {}^{2} log_{}(16) - {}^{3} log(27) + {}^{5} log(1) \\ {}^{2} log(2 {}^{4} ) - {}^{3} log(3 {}^{3} ) + {}^{5} log(1) \\ 4 - 3 + 0 \\ 1[/tex]
    semoga membantu.........

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