Matematika

Pertanyaan

integral (4x+7)(2x^2+7x+3)^2 dx

1 Jawaban

  • misal :
    u = 2x² + 7x + 3
    du/dx = 4x + 7
    (4x + 7) dx = du

    ∫(4x + 7)(2x² + 7x + 3)² dx
    = ∫u² du
    = 1/3 u³ + C
    = 1/3 (2x² + 7x + 3)³ + C

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