Hitunglah ph larutan berikut : larutan 6 gr asam asetat dalam 200 ml air (ka= 10 pangkat min5)

Mr asam = 60

M asam = massa / (volume x Mr)
M asam = 6 / (0,2 x 60)
M asam = 0,5 M

[H+] = √(Ka x M)
[H+] = √(10^-5 x 5 x 10^-1)
[H+] = √(5 x 10^-6)
[H+] = √5 x 10^-3 M
pH = 3 - log√5