diketahui fungsi f(x)= (2x^3+5) (3x^4-2) nilai turunan pertama f(x)

f (x) = u(x).v(x)
f' (x) = u'(x).v(x) + u(x).v'(x)
f (x) = (2x^3 +5)(3x^4-2)
misal u(x) = 2x^3+5 => u'(x) = 6x^2
v(x) = 3x^4-2 => v'(x) = 12x^3
f' (x) = (6x^2)(3x^4-2)+ (2x^3+5)(12x^3)
f' (x) = 18x^6 - 12x^2 + 24x^6+60x^3
f' (x) = 42x^6 +60x^3 -12x^2.