tolong di bantu besok sudah dikumpulkan

lim [x-->1/2] (2x - 1)/(4x² - 1)
= lim [x-->1/2] (2x - 1)/(2x - 1)(2x + 1)
= lim [x-->1/2] 1/(2x + 1)
= 2 . 1/2 + 1
= 1 + 1
= 2

lim [x-->2] (x² - 5x + 6) / (x² + 2x - 8)
= lim [x-->2] (x - 3)(x - 2) / (x + 4)(x - 2)
= lim [x-->2] (x - 3)/(x + 4)
= (2 - 3)/(2 + 4)
= -1/6

•••

lim [x--->5] (5t - 1/2 t²)
= 5 . 5 - 1/2 . 5²
= 25 - 12,5
= 12,5