integral tak tentu dari soal di atas

jawab

(0..2)∫ (3x + 2)³ dx
u = 3x + 2
du = 3 dx
dx = 1/3 du

x= 0 --> u = 2
x = 2 --> u = 8

(2..8) ∫ 1/3  u³ du

= 1/3 . 1/4 . u⁴] (8...2)

= 1/12 (8⁴ - 2⁴)
 
= 1/12 (4.080) = 340