Diketahui f(x) = x²-2/2x+1. Jika f'(x) menyatakan turunan pertama f(x), nilai f(0) + 2f'(0)=

f(x) = (x² - 2) / (2x + 1)
f(0) = (0² - 2) / (2(0) + 1) = -2
U = x² - 2 ; u' = 2x
V = 2x + 1 ; v' = 2

f' (x) = (u'v - uv') / v²
f'(x) = (2x(2x + 1) - (2x² - 2)(2) ) / (2x + 1)²
f'(x) = (4x² + 2x - 4x² + 4) / (2x + 1)²
f'(x) = (2x + 4) / (2x + 1)²
f'(0) = (2(0) + 4) / (2(0) + 1)² = 4

f(0) + 2 f'(0)
= -2 + 2 (4) = -2 + 8 = 6