fungsi f(x)=3x+2 dan g(x)=2x+p,dengan f:R→R dan g:R→R,jika fog(x)=gof(x) maka nilai p=

jawab

f(x) = 3x + 2
g(x)= 2x +p

fog(x)= gof(x)
f(2x+p) = g(3x+2)

3(2x+p) + 2 = 2(3x+2) + p
6x + 3p + 2 = 6x + 4 + p
3p - p = 4- 2
2p = 2
p = 1