ada yang bisa bantu?

f(x) = (2x - 1)/(x + 3)
u = 2x - 1
u' = 2
v = x + 3
v' = 1
f'(x) = (u'v - uv')/v²
f'(x) = (2(x + 3) - (2x - 1))/(x+3)²
f'(x) = (2x + 6 - 2x + 1)/(x + 3)²
f'(x) = 7/(x + 3)²
f'(2) = 7/(2 + 3)² = 7/25