Diketahui larutan NH4OH 0,1 M mempunyai ph 11. Hitung ph dari larutan (NH4)2SO4 0,1 M

pH = 11 ... pOH = 3
OH- = sqrt KbMb
3 = -log sqrt Kb.0.1
sqrt 0.1. Kb = 10'-3
Kb = 10'-5

Kh = Kw/Kb= 10-'14/10'-5 = 10'-9
pH = -log sqrt Kh*Mgaram
pH = -log sqrt(10'-9 * 0.1)
pH = - log 10'-5
pH = 5