tolong jawab kak.. [tex] \sqrt[4]{ {16}^{3} } - \sqrt[3]{ {27}^{2} } = [/tex]

Operasi Bentuk Akar

[tex] \sqrt[4]{ {16}^{3} } - \sqrt[3]{ {27}^{2} } = {16}^{ \frac{3}{4} } - {27}^{ \frac{2}{3} } \\ \\ = { ({2}^{4} )}^{ \frac{3}{4} } - {( {3}^{3}) }^{ \frac{2}{3} } \\ \\ = {2}^{3} - {3}^{2} \\ = 8 - 9 \\ = - 1[/tex]


*semoga membantu. sukses selalu ^_^