Kak please Bantu donk bsk dikumpul nmr 6 ajh. Klo nmr 7 bsa gpp

x^2-2x-5=0
a=1, b=-2, c=-5

[tex]x = \frac{ - b + \sqrt{{b}^{2} - 4ac} }{2a} \\ x = \frac{2 + \sqrt{ {2}^{2} - (4 \times 1 \times - 5)} }{2 \times 1} \\ x = \frac{2 + \sqrt{4 + 20} }{2} \\ x = \frac{2 + 2\sqrt{3} }{2} \\ x = 1 + \sqrt{3} [/tex]
atau

[tex]x = \frac{ - b - \sqrt{{b}^{2} - 4ac} }{2a} \\ x = \frac{2 - \sqrt{ {2}^{2} - (4 \times 1 \times - 5)} }{2 \times 1} \\ x = \frac{2 - \sqrt{4 + 20} }{2} \\ x = \frac{2 - 2\sqrt{3} }{2} \\ x = 1 - \sqrt{3} [/tex]

jadi:

[tex] \frac{1}{ { \alpha }^{2} } + \frac{1}{ { \beta }^{2} } \\ = \frac{1}{ {(1 + \sqrt{3} )}^{2} } + \frac{1}{ {(1 - \sqrt{3} )}^{2} } \\ = \frac{?}{?} [/tex]