Diketahui segitiga ABC siku-siku di C.jika besar sudutA=30° dan panjang AC=8 cm.tentukan sudut B,panjang AB,dan BC

∠B = 90° - 30° = 60°

AB = AC/cos∠A
= 8/cos 30°
= 8/(1/2√3)
= 16/√3
= (16/3)√3 cm

BC = AB x sin∠A
= (16/3)√3 x sin 30°
= (16/3)√3 x (1/2)
= (16/6)√3 cm

semoga membantu ^^