Nilai maksimum dan minimum F (x)= 2sinx - x pada interval [0,phi/2].

jawab

f(x ) = 2 sinx  - x
f '(x) = 0
2cos x - 1 = 0
cos x = 1/2 
x = 60
x = π/3

f(π/3)  = 2 sin (π/3) - (π/3)
nilai min = 2(1/2 √3) - (π/3) = √3 - (π/3)