3×+2y=13..(1) 2×+y=8..(2) tolong jawab pake caranya

3x + 2y = 13 (x1)
2x + y = 8 (x2)

3x+2y = 13
4x+2y = 16 (kemudian dikurangkan/eliminasi)
=> -x = -3
=> x = 3

3x+2y = 13
3(3)+2y = 13
9+2y = 13
2y = 13-9
2y = 4
y = 2

3x+2y=13 ...........(1)
2x+y=8 .............(2)
eliminasi:
3x+2y=13 x1
2x+y=8 x2
....................................
3x+2y=13
4x+2y=16
.........................--
-x=-3
x=3
substitusikan nilai x ke persamaan (1) atau (2)
2x+y=8
2(3)+y=8
6+y=8
y=8-6
y=2
semoga membantu.....