Matematika

Pertanyaan

tolong bantu,please !
tolong bantu,please !

1 Jawaban


  • [tex] {ac}^{2} = {ab}^{2} + {bc}^{2} \\ {39}^{2} = {36}^{2} + {bc}^{2} \\ {bc}^{2} = 225 \\ bc = 15 \\ \\ \sin( \beta ) = \frac{bc}{ac} = \frac{15}{39} = \frac{5}{13} \\ \cos( \beta ) = \frac{ab}{ac} =\frac{36}{39} = \frac{12}{13} \\ \tan( \beta ) = \frac{bc}{ab} = \frac{15}{36} = \frac{5}{12} \\ \csc( \beta ) = \frac{1}{ \sin( \beta ) } = \frac{13}{5} \\ \sec( \beta ) = \frac{1}{ \cos( \beta ) } = \frac{13}{12} \\ \cot( \beta ) = \frac{1}{ \tan( \beta ) } = \frac{12}{5} [/tex]