Jika f(x)adalah turunan pertama dari f(x)=(3×-3)(2×+5), maka nilai f(2) adalah....

f(x) = u . v
f(x) = (3x - 3)(2x + 5)

f'(x) = u'v + v'u
f'(x) = 3(2x + 5) + 2(3x - 3)
f'(x) = 6x + 15 + 6x - 6
f'(x) = 12x + 9

f'(2) = 12.2 + 9
f'(2) = 24 + 9
f'(2) = 33

f(x) = (3x - 3)(2x + 5)
f(x) = 6x² + 15x - 6x - 15
f(x) = 6x² + 9x - 15

f'(x) = 2(6)x^(2-1) + (1)9x^(1-1) - 0
f'(x) = 12x¹ + 9x^0 - 0
f'(x) = 12x + 9(1)
f'(x) = 12x + 9

f'(2) = 12(2) + 9
f'(x) = 24 + 9
f'(x) = 33