Matematika

Pertanyaan

tentukan unsur yang diminta dari deret aritmatika berikut
1. a=2, s22=737, b=
2. b=5, u10=46, s15=
3. u4=9, u7=18, s10=

1 Jawaban

  • Sn = 1/2n [ 2a + ( n – 1 ) b ] <<== acuan

    Un = a + (n-1) b <<==== acuan



    1. a = 2 , S22 = 737 , b =....???

    Sn = 1/2n [ 2a + ( n – 1 ) b ]

    s22 = 22/2 [ 2 (2) + (21) b ]

    737 = 11 [ 4 + 21 b ]

    737 / 11 = 4 + 21 b

    21 b = 67 - 4

    b = 63/21

    b = 3 ===>>> lets Rock



    2. b = 5 , u10 = 46 , s15..???

    Un = a + (n-1) b

    U10 = a + (9) 5

    46 = a + 45

    a = 1 <<====

    Sn = 1/2n [ 2a + ( n – 1 ) b ]

    s15 = 15/2 ( 2(1) + 14 (5) )

    s15 = 15/2 ( 72 )

    s15 = 540 <<==== Rock It



    3. u4 = 9 , u7 = 8 , s10...????

    U4 = 9
    a + 3b = 9

    a = 9 - 3b ==>>> acuan

    U7 = 8
    a + 6b = 8

    9 - 3b + 6b = 8

    3b = 8 - 9

    b = -1/3 ==>_ subs ke nilai U4 utk nilai a

    a + 3b = 9

    a + 3 (-1/3) = 9

    a - 1 = 9

    a = 10 <<====

    Sn = 1/2n [ 2a + ( n – 1 ) b ]

    S10 = 10/2 [2 (10) + 9 (-1/3) ]

    S10 = 5 [ 20 - 3 ]

    s10 = 5 ( 17 )

    s10 = 85 ===>__ Rock Finish

Pertanyaan Lainnya