Matematika

Pertanyaan

sederhanakan
A. 2√6+3√24-√96
B. 5/8-✓6
C. ✓8/✓11+✓3

1 Jawaban

  • a.
    [tex]2 \sqrt{6} + 3 \sqrt{6 \times 4} - \sqrt{16 \times 6} \\ = 2 \sqrt{6} + 3(2) \sqrt{6} - 4 \sqrt{6} \\ = 2 \sqrt{6} + 6 \sqrt{6} - 4 \sqrt{6} \\ = 4 \sqrt{6} [/tex]
    b.
    [tex] \frac{5}{8 - \sqrt{6} } \times \frac{8 + \sqrt{6} }{8 + \sqrt{6} } = \frac{40 + 5 \sqrt{6} }{64 - 6} \\ = \frac{40 + 5 \sqrt{6} }{58} [/tex]
    c.
    [tex] \frac{ \sqrt{8} }{ \sqrt{11} + \sqrt{3} } \times \frac{ \sqrt{11} - \sqrt{3} }{ \sqrt{11} - \sqrt{3} } \\ = \frac{ \sqrt{88} - \sqrt{24} }{11 - 3} \\ = \frac{ \sqrt{88} - \sqrt{24} }{8} \\ = \frac{ \sqrt{4 \times 22} - \sqrt{4 \times 6} }{8} \\ = \frac{2 \sqrt{22} - 2 \sqrt{6} }{8} = \frac{2 (\sqrt{22} - \sqrt{6} )}{8 } \\ = \frac{ \sqrt{22} - \sqrt{6} }{4} [/tex]

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